10 Derived classes [class.derived]

Virtual functions support dynamic binding and object-oriented programming. A class that declares or inherits a virtual function is called a polymorphic class.

If a virtual member function vf is declared in a class Base and in a class Derived, derived directly or indirectly from Base, a member function vf with the same name, parameter-type-list ([dcl.fct]), cv-qualification, and ref-qualifier (or absence of same) as Base::vf is declared, then Derived::vf is also virtual (whether or not it is so declared) and it overrides111 Base::vf. For convenience we say that any virtual function overrides itself. A virtual member function C::vf of a class object S is a final overrider unless the most derived class ([intro.object]) of which S is a base class subobject (if any) declares or inherits another member function that overrides vf. In a derived class, if a virtual member function of a base class subobject has more than one final overrider the program is ill-formed. [ Example:

struct A {
  virtual void f();
};
struct B : virtual A {
  virtual void f();
};
struct C : B , virtual A {
  using A::f;
};

void foo() {
  C c;
  c.f();              // calls B::f, the final overrider
  c.C::f();           // calls A::f because of the using-declaration
}

 — end example ]

[ Example:

struct A { virtual void f(); };
struct B : A { };
struct C : A { void f(); };
struct D : B, C { };  // OK: A::f and C::f are the final overriders
                      // for the B and C subobjects, respectively

 — end example ]

[ Note: A virtual member function does not have to be visible to be overridden, for example,

struct B {
  virtual void f();
};
struct D : B {
  void f(int);
};
struct D2 : D {
  void f();
};

the function f(int) in class D hides the virtual function f() in its base class B; D::f(int) is not a virtual function. However, f() declared in class D2 has the same name and the same parameter list as B::f(), and therefore is a virtual function that overrides the function B::f() even though B::f() is not visible in class D2.  — end note ]

If a virtual function f in some class B is marked with the virt-specifier final and in a class D derived from B a function D::f overrides B::f, the program is ill-formed. [ Example:

struct B {
  virtual void f() const final;
};

struct D : B {
  void f() const;     // error: D::f attempts to override final B::f
};

 — end example ]

If a virtual function is marked with the virt-specifier override and does not override a member function of a base class, the program is ill-formed. [ Example:

struct B {
  virtual void f(int);
};

struct D : B {
  virtual void f(long) override;  // error: wrong signature overriding B::f
  virtual void f(int) override;   // OK
};

 — end example ]

Even though destructors are not inherited, a destructor in a derived class overrides a base class destructor declared virtual; see [class.dtor] and [class.free].

The return type of an overriding function shall be either identical to the return type of the overridden function or covariant with the classes of the functions. If a function D::f overrides a function B::f, the return types of the functions are covariant if they satisfy the following criteria:

• (7.1)

  both are pointers to classes, both are lvalue references to classes, or both are rvalue references to classes112

• (7.2)

  the class in the return type of B::f is the same class as the class in the return type of D::f, or is an unambiguous and accessible direct or indirect base class of the class in the return type of D::f

• (7.3)

  both pointers or references have the same cv-qualification and the class type in the return type of D::f has the same cv-qualification as or less cv-qualification than the class type in the return type of B::f.

If the return type of D::f differs from the return type of B::f, the class type in the return type of D::f shall be complete at the point of declaration of D::f or shall be the class type D. When the overriding function is called as the final overrider of the overridden function, its result is converted to the type returned by the (statically chosen) overridden function ([expr.call]). [ Example:

class B { };
class D : private B { friend class Derived; };
struct Base {
  virtual void vf1();
  virtual void vf2();
  virtual void vf3();
  virtual B*   vf4();
  virtual B*   vf5();
  void f();
};

struct No_good : public Base {
  D*  vf4();        // error: B (base class of D) inaccessible
};

class A;
struct Derived : public Base {
    void vf1();     // virtual and overrides Base::vf1()
    void vf2(int);  // not virtual, hides Base::vf2()
    char vf3();     // error: invalid difference in return type only
    D*  vf4();      // OK: returns pointer to derived class
    A*  vf5();      // error: returns pointer to incomplete class
    void f();
};

void g() {
  Derived d;
  Base* bp = &d;                // standard conversion:
                                // Derived* to Base*
  bp->vf1();                    // calls Derived::vf1()
  bp->vf2();                    // calls Base::vf2()
  bp->f();                      // calls Base::f() (not virtual)
  B*  p = bp->vf4();            // calls Derived::pf() and converts the
                                // result to B*
  Derived*  dp = &d;
  D*  q = dp->vf4();            // calls Derived::pf() and does not
                                // convert the result to B*
  dp->vf2();                    // ill-formed: argument mismatch
}

 — end example ]

[ Note: The interpretation of the call of a virtual function depends on the type of the object for which it is called (the dynamic type), whereas the interpretation of a call of a non-virtual member function depends only on the type of the pointer or reference denoting that object (the static type) ([expr.call]).  — end note ]

[ Note: The virtual specifier implies membership, so a virtual function cannot be a nonmember ([dcl.fct.spec]) function. Nor can a virtual function be a static member, since a virtual function call relies on a specific object for determining which function to invoke. A virtual function declared in one class can be declared a friend in another class.  — end note ]

A virtual function declared in a class shall be defined, or declared pure ([class.abstract]) in that class, or both; but no diagnostic is required ([basic.def.odr]).

[ Example: here are some uses of virtual functions with multiple base classes:

struct A {
  virtual void f();
};

struct B1 : A {                 // note non-virtual derivation
  void f();
};

struct B2 : A {
  void f();
};

struct D : B1, B2 {             // D has two separate A subobjects
};

void foo() {
  D   d;
//   A*  ap = &d;                  // would be ill-formed: ambiguous
  B1*  b1p = &d;
  A*   ap = b1p;
  D*   dp = &d;
  ap->f();                      // calls D::B1::f
  dp->f();                      // ill-formed: ambiguous
}

In class D above there are two occurrences of class A and hence two occurrences of the virtual member function A::f. The final overrider of B1::A::f is B1::f and the final overrider of B2::A::f is B2::f.

The following example shows a function that does not have a unique final overrider:

struct A {
  virtual void f();
};

struct VB1 : virtual A {        // note virtual derivation
  void f();
};

struct VB2 : virtual A {
  void f();
};

struct Error : VB1, VB2 {       // ill-formed
};

struct Okay : VB1, VB2 {
  void f();
};

Both VB1::f and VB2::f override A::f but there is no overrider of both of them in class Error. This example is therefore ill-formed. Class Okay is well formed, however, because Okay::f is a final overrider.

The following example uses the well-formed classes from above.

struct VB1a : virtual A {       // does not declare f
};

struct Da : VB1a, VB2 {
};

void foe() {
  VB1a*  vb1ap = new Da;
  vb1ap->f();                   // calls VB2::f
}

 — end example ]

Explicit qualification with the scope operator ([expr.prim]) suppresses the virtual call mechanism. [ Example:

class B { public: virtual void f(); };
class D : public B { public: void f(); };

void D::f() { /* ... */ B::f(); }

Here, the function call in D::f really does call B::f and not D::f.  — end example ]

A function with a deleted definition ([dcl.fct.def]) shall not override a function that does not have a deleted definition. Likewise, a function that does not have a deleted definition shall not override a function with a deleted definition.