A constructor declared without the function-specifier explicit specifies a conversion from the types of its parameters to the type of its class. Such a constructor is called a converting constructor. [ Example:
struct X { X(int); X(const char*, int =0); }; void f(X arg) { X a = 1; // a = X(1) X b = "Jessie"; // b = X("Jessie",0) a = 2; // a = X(2) f(3); // f(X(3)) }
— end example ]
An explicit constructor constructs objects just like non-explicit constructors, but does so only where the direct-initialization syntax ([dcl.init]) or where casts ([expr.static.cast], [expr.cast]) are explicitly used. A default constructor may be an explicit constructor; such a constructor will be used to perform default-initialization or value-initialization ([dcl.init]). [ Example:
struct Z { explicit Z(); explicit Z(int); }; Z a; // OK: default-initialization performed Z a1 = 1; // error: no implicit conversion Z a3 = Z(1); // OK: direct initialization syntax used Z a2(1); // OK: direct initialization syntax used Z* p = new Z(1); // OK: direct initialization syntax used Z a4 = (Z)1; // OK: explicit cast used Z a5 = static_cast<Z>(1); // OK: explicit cast used
— end example ]
A non-explicit copy/move constructor ([class.copy]) is a converting constructor. An implicitly-declared copy/move constructor is not an explicit constructor; it may be called for implicit type conversions.